Reverse bits of the given number, and return new number

Reverse bits of the given number, and return new number

#!/usr/bin/env python3

# Function to reverse bits of the given number and return new number
def reverse_bits(n):
    rev = 0
     
    # traversing bits of 'n' from the right
    while (n > 0) :
         
        # bitwise left shift 'rev' by 1
        rev = rev << 1
         
        # if current bit is '1'
        if (n & 1 == 1) :
            rev = rev ^ 1
         
        # bitwise right shift 'n' by 1
        n = n >> 1
         
     
    # required number
    return rev